Time issues: milliseconds

Comments

• Andresan

  July 2014 edited July 2014 Posts: 35

  I am dumb.... Weeks figuring why.... Is ElapsedTime... Not ESlapsedTime....

  [/Thread]
• Doge

  July 2014 Posts: 135

  Codea measures in frames (60 frames per second) so that can be used to figure out when the next second is coming
• dave1707 Mod

  July 2014 Posts: 8,452

  @Doge The speed of draw() varies depending on the amount of objects are on the screen. So frames vary from 60 FPS to below 1 FPS, which make it useless for accurate time.
• LoopSpace

  July 2014 Posts: 490

  There's also the os time functions which can be used for more accurate timings.
• dave1707 Mod

  July 2014 Posts: 8,452

  os.clock() will give you CPU time in fractions of a second. If you need a quick time difference, that might work. os.time() will give you seconds and should be use over a longer time period.
• Andresan

  July 2014 Posts: 35

  i managed to sync a flashing image to a music's beat, the sync would not be lost but the accuracy is medium... I will post an example...
• Andresan

  July 2014 Posts: 35

  Here an example of music sync:

   -- Syncing Test
  
  function setup()
      music("A Hero's Quest:Battle",1)
      isrestarted=readGlobalData("restarted",false)
      bpm=105
      beattime=60/bpm
      beatcount=1
      starttime=ElapsedTime
      delay=0.05
      parameter.watch("ElapsedTime")
      parameter.watch("beatcount")
      parameter.boolean("SomeOverload")
      parameter.boolean("LotOfCalcs")
      currentcolor=0
  end
  
  
  function draw()
      background(0,currentcolor,0)
      if currentcolor>4 then
          currentcolor = currentcolor - 4
      end
      if ElapsedTime>=starttime+(beattime*beatcount) + delay then
          beatcount = beatcount + 1
          currentcolor=70
      end
      if isrestarted==false then
          saveGlobalData("restarted",true)
          text("Please for correct sync press restart now.",300,10)
      end
      if SomeOverload==true then
          sprite(CAMERA,WIDTH/2,HEIGHT/2,200,200)
      end
      if LotOfCalcs==true then
          for i=1, 30000 do
              a=math.log10(i)*math.tan(i)
          end
      end
  end